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The alias structure may be found by multiplying each effect column by the de ning relation Care should be exercised in choosing the generators so that effects of potential interest are not aliased with each other Each effect has 2p 1 aliases For moderately large values of k, we usually assume higher order interactions (say, third- or fourth-order or higher) to be negligible, and this greatly simpli es the alias structure It is important to select the p generators for the 2k p fractional factorial design in such a way that we obtain the best possible alias relationships A reasonable criterion is to select the generators so that the resulting 2k p design has the highest possible design resolution Montgomery (2001) presents a table of recommended generators for 2k p fractional factorial designs for k 15 factors and up to as many as n 128 runs.

The current implementation of DART is designed to work with the singlemachine simulation environment. Specifically, the simulation is started by launching an independent Java process for each simulated node in the network. For instance, in a 20-node network, twenty instances of DART (with different command-line arguments) will be started on the same machine.

var themTharHills:String = "hillshillshillsGOLDhills"; trace(themTharHills.search(/gold/i)); //15

A portion of his table is reproduced here as Table 14-29 In this table, the generators are shown with either or choices; selection of all generators as will give a principal fraction, while if any generators are choices, the design will be one of the alternate fractions for the same family The suggested generators in this table will result in a design of the highest possible resolution Montgomery (2001) also gives a table of alias relationships for these designs..

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This snippet sees if there is gold in them thar hills. Indeed, there is, starting at the fteenth character: after three hills, which have ve characters each. If you were just searching for the lowercase string gold, that would be too boring; after all, you learned how to search for substrings in 6,

Fractional Factorial Designs Number of Runs 4 8 16 8 32 16 8 C D E D E F E F D E F G E G E F G D E F G G H F G H E F G H H J G H J F G H J E F G H J Design Generators AB ABC ABCD AB AC ABCDE ABC BCD AB AC BC ABCDEF ABC ABDE ABC BCD ACD AB AC BC ABC ABCD ABEF ABC ABD BCDE BCD ACD ABC ABD ACDFG BCEFG ABCD ACEF CDEF BCDE ACDE ABDE ABCE ABC BCD ACD ABD ABCD Number of Factors k 10 210 V

Design Generators ABCG ACDE ACDF BCDF ACDF ABDE ABCE ABCD ABCE ABDE ACDE BCDE ABC BCD ACD ABD ABCD AB CDE ABCD ABF BDEF ADEF ABC BCD CDE ACD ADE BDE ABC BCD ACD ABD ABCD AB AC

Text, Strings, and Characters. Instead, you passed it a regular expression that matches any pattern of the letters g, o, l, and d in either case, using the ag for case insensitivity, i. This matched the uppercase GOLD. Not very well hidden, that gold. It would have also matched gOLd, GOLd, and the other 13 permutations of capitalizations.

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The exec() method of RegExp is a useful one, as Example 12-2 shows. You can use it to locate and identify patterns, and it plays nicely with loops. First let s use it to locate a pattern:

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var searchForGold:RegExp = /gold/gi; var themTharHills:String = "hillsgoldhillshillsGOLDhills"; var result:Object = searchForGold.exec(themTharHills); //TEST if there s gold in the hills if (result) trace("There s gold in them thar hills!"); //LOCATE the gold trace(result.index); //5 //look a second time result = searchForGold.exec(themTharHills); //output the second location trace(result.index); //19

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You can see you re already getting more intricate Here you have created a regular expression that nds the word gold in any combination of uppercase and lowercase in the string you pass it It is also con gured to match all instances of the pattern In the second paragraph, you execute the regular expression once The expression goes through the string from beginning to end and stops when it nds the rst match, the lowercase gold after the rst hill The exec() method returns null if there are no (more) matches of the pattern; otherwise it returns an object with lots of useful data The return type of exec(), and the variable result it is assigned to, is Object First, you use this Object in a Boolean context to see if there are any matches of the pattern.

Source: Montgomery (2001)

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