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such as POP3 or IMAP. In the preceding code, the actual network connection to the e-mail server is established by retrieving a Store based on the protocol entered in the Connect dialog box and then calling its connect( ) method. First, a URLName object is instantiated with the connection URL constructed earlier using data entered in the Connect dialog box. The URLName object is then passed to the session s getStore( ) method. The getStore( ) method returns a Store object based on the URLName object s protocol. After the store has been retrieved, its connect( ) method is invoked. Remember that POP3 servers only support the notion of one folder, whereas IMAP servers can have multiple folders. Thus, once the connection has been successfully established with the e-mail server, the default INBOX folder is opened and its messages are retrieved as shown in the following code:

We assume that, for practical purposes, the output of the lter can be considered to be negligibly small for all frequencies in the stopband We must remember that a low-pass lter is used in applications where it is desired to pass all signal components below a speci ed frequency and reject all components above that frequency It therefore follows that the width of the transition band is especially critical, and should be as narrow as possible so as to prevent, as much as possible, the passage of unwanted higher frequency components through the lter As you would expect, it s possible to design low-pass lters having frequency response curves GREATLY SUPERIOR to those of the simple RC and RL lters illustrated in Fig 199.

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To do this requires the use of both inductance and capacitance (L and C), arranged in various ways, making use of the phenomenon of series and parallel resonance One such arrangement is known as the constant-k type of lter, and is the subject of the next two sections Before getting into these sections, however, we must rst take up the symmetrical T network, as follows Let us begin by referring back to the standard T network notation of Fig 174 in section 92 Let us then de ne that a symmetrical T network is a T network in which Z1 Z2 Thus, Fig 174 could be redrawn to represent a symmetrical T as shown in Fig 200..

// Download message headers from server. try { // Open main "INBOX" folder. Folder folder = store.getFolder("INBOX"); folder.open(Folder.READ_WRITE); // Get folder's list of messages. Message[] messages = folder.getMessages();

Actually, however, the notation of Fig. 200 is not used in the SPECIAL CASE of the symmetrical T network; instead, it has become the custom to denote each of the series " " elements by Z1 =2 and the shunt element by Z2 , as shown in Fig. 201. This will cause no di culties so long as we remember that the special notation in Fig. 201 is to be used ONLY for the case of the symmetrical T network. In Fig. 201, terminals (1, 1) are given to be the INPUT terminals and (2, 2) the OUT" PUT terminals. Now suppose a load impedance ZL is connected to the output terminals in " Fig. 201; doing this will cause a certain value of INPUT IMPEDANCE, Zin , to appear at the input terminals as shown in Fig. 202. Note that, looking into terminals (1, 1) in Fig. 202, we see a series-parallel circuit " " " " consisting of Z1 =2 in series with the parallel combination of Z2 and (Z1 =2 ZL ). Thus

If Y and N are not integers (whole numbers), exactly the same procedure is used, but we must remember to line up the binary points just as we line up the decimal points in decimal addition. For example, suppose we are to nd Y N where, let us say, Y 1 1 0 1 : 0 1 1 0 decimal 13:3750 N 1 0 0 1 : 1 0 1 1 decimal 9:6875 Note that the answer in decimal notation is Y N 13:3750 9:6875 3:6875. To work out the problem let us use the 1 s complement of N in the usual way; thus Y 1 1 0 1 : 0 1 1 0 1 s comp of N 0 1 1 0 : 0 1 0 0 r 0 0 1 1 : 1 0 1 0 j 1 ! ! 0 0 1 1 : 1 0 1 1; answer dec: 3:6875

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