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The I element, as well as the H1 element, will be red in color. However, there are many times when you may want to override inheritance and have, instead, a speci c CSS property show up. In those cases, contextual selectors are the key. A contextual selector is one that speci es that one element, when contained within another, is to

CHAPTER 17 Off-Axis Reflection Holography The new diagram, with the object and reference on different sides of the plate, is the equivalent reflection hologram exposure geometry Of course, we could also have done the same process in reverse, starting with a reflection hologram and working our way to the corresponding transmission hologram exposure geometry Continuing this example, let s figure out where light from a reflection hologram goes For now, ignore the wavelength-selective effect of the volume grating Beginning with the reflection hologram exposure geometry, we use the above technique to find the dual transmission hologram by flipping the reference beam across the plate ( Duals are often used in science to help relate less understood problems to ones we already understand.

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When a movie is inserted into a Container field, only a reference to the movie file is actually stored in the database (rather than the movie itself). This means that if you move the database or the movie (for example, by giving it to someone else or by copying it onto a removable medium such as a disk cartridge), the references to the movies become unresolved. Such unresolved references will result in a prompt to the user saying that the file could not be found. When importing a picture, on the other hand, the actual picture is stored in the database unless you mark the Store only a reference to the file check box.

) We then simulate or calculate the output beams for the +1 (or possibly -1, if the hologram is illuminated in phase conjugate mode) output orders, using our knowledge of transmission holography to choose an appropriate illumination angle and position Once we calculate the illumination and output information, we convert to reflection mode by flipping the illumination back across the plane of the hologram At this point, the output rays, and the viewer, will be on the same side of the hologram as the illumination source After you ve performed this exercise a few times, you ll gain enough intuition about the relationship between transmission and reflection geometry that you ll be able to think in reflection terms natively .

ith the release of Internet Explorer 5, Microsoft s browser began to establish dominance and appeared to be on the right track to becoming the de facto standard Although that version of Internet Explorer still had a significant number of bugs and unsupported features, subsequent releases have improved on its increasingly solid base of CSS compliance Unfortunately, browser development largely halted with the release of Internet Explorer 6, Service Pack 1 in September 2002 Microsoft has said that there will no further updates to the standalone browser, and the next major revision will not be available until the latest operating system (code-named Longhorn) is available Even more unfortunately, the cracks in Internet Explorer 6 s CSS support are becoming quite apparent From the Netscape side of the browser war, a stunning defeat appears to have been turned into a victory for designers.

An interesting property of this flipping of the refererence and illumination rays is that it is completely compatible with our transmission holography angle calculator, the sin theta equation, at least if we re careful Recall from trigonometry that sine = sin(l80 - 0) (1) That s our flip (refer to the preceding figure), but it also means that = for object, reference, illumination, and sin ~utransmission sin erereflection output beams In practice, then, this mathematical equivalence means we can use the sine equation as we always have in transmission holography, but apply it as well for predicting the behavior of reflection holograms, We do need to keep our wits about us, though When it comes time to take the inverse sine function to solve for our unknown variable, the equation provides us no guidance about which solution (on which side of the plate) to choose.

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