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To test several conditions, define several blocks of statements where a statement is executed only when its condition is met. For example: If <condition1> Then <statement block 1> Else If <statement block 2> Else <statement block 3> End If If <condition1> returns True, Visual Basic executes the statements following the Then keyword. Visual Basic ignores the statements in <statement block 2> and <statement block 3>, continuing execution with the statements following the End If keywords. If <condition1> returns False, Visual Basic executes the statements following the Else If keywords, if supplied. Visual Basic ignores the statements in <statement block 1> and <statement block 3>, continuing execution with the statements following the End If keywords. You may use any number of Else If statements, but only one Else statement, in an If ... Then ... Else statement.

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COMPLEX NUMBERS, POLAR FORM 1.73. Perform each of the indicated operations: 5 10 1 i 10 c ; ; d 3 4i 4 3i 1 i Ans. (a) 1 4i, (b) 9 46i, (c)

Find the derivative of y= x 2 8x + 5 (2x 1)3

11 5

Instead of using the product and quotient rule for differentiation, it is easier to nd the logarithm of the absolute values,1 ln |y| = ln x 2 8x + 5 (2x 1)3 [by Property 6] [by Property 5] [by Property 8]

(a) 2 5 3i 3 2 i 5 i 3 , (b) 3 2i 3 2 4i 2 1 i 2 3i 4 2i e f : 5 7i ; 1 2i 2 1 i (d) 1, (e)

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= ln (x 2 8x + 5) ln |2x 1|3 = ln (x 2 ) + ln (8x + 5)1/2 ln |2x 1|3 = 2 ln x + 1 ln (8x + 5) 3 ln |2x 1| 2

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When you evaluate more than two conditions, it often makes more sense to use the Select Case control structure. When you want to selectively execute a block of statements from a choice of many, use the Select Case structure, as in this example: Select Case <TestExpression> Case <ExpressionList> <statements> . . . Case Else <statements> End Select The Select Case structure begins with a single test expression. Visual Basic evaluates it once and compares it with each Case statement in the structure. When Visual Basic finds a match, it executes the associated block of statements. The <ExpressionList> may contain one or more values separated by commas. The statement may contain zero or more statements. Visual Basic executes only <statements> associated with the first match to the <TestExpression>. After those <statements> are completed, execution continues with any statements following the End Select keywords. You can include an optional Case Else statement that Visual Basic executes if it finds no Case matches. This example shows how the Select Case structure works: Select Case UCase(ColorName) Case "RED" Layer.Color = acRed Case "YELLOW" Layer.Color = acYellow Case "GREEN" Layer.Color = acGreen Case "CYAN" Layer.Color = acCyan Case "BLUE" Layer.Color = acBlue Case "MAGENTA" Layer.Color = acMagenta Case "WHITE" Layer.Color = acWhite

10 37,

1 We take the absolute values to make sure that the logarithm is de ned. In practice, we shall omit the absolute values when it is clear that the functions are nonnegative.

2 i, 5

and then to differentiate, 1 1 Dx y = 2 y x Therefore, Dx y = y 4 6 2 + x 8x + 5 2x 1 = + 2 4 6 1 1 1 8 3 2 = + 2 8x + 5 2x 1 x 8x + 5 2x 1 4 6 x 2 8x + 5 2 + 8x + 5 2x 1 (2x 1)3 x

16 5

2 i. 5

Case Else If CInt(ColorName) > 0 And CInt(ColorName) < 256 Then Layer.Color = CInt(ColorName) Else MsgBox UCase(ColorName) & " is an invalid color name", _ vbCritical, "Invalid Color Selected" End If End Select Another way to format Select Case is to put the return statements on the same line as the Case statements. This keeps the code format simpler when you have a small set of cases. Type a colon (:) after the Case statement to separate it from the return statement code: Select Case Ucase(ColorName) Case RED: Layer.Color = acRed Case BLUE: Layer.Color = acBlue End Select While the Select Case evaluates a single test expression at the top of the structure, the If ... Then ... Else structure evaluates a different expression for each Else ... If statement. Therefore, you replace an If ... Then ... Else structure with a Select Case statement if each Else If statement evaluates the same expression but looks for different values.

This procedure of rst taking the logarithm and then differentiating is called logarithmic differentiation.

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